For a normal eye,the cornea of the eye provid | vedclass

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(C) The total converging power of the eye is the sum of the power of the cornea and the eye lens.Total power $P = P_{c} + P_{e} = 40\, D + 20\, D = 60

Vedclass · Accepted Answer

$1.67$

Vedclass · Answer

(C) The total converging power of the eye is the sum of the power of the cornea and the eye lens.Total power $P = P_{c} + P_{e} = 40\, D + 20\, D = 60\, D$.For a normal eye,the image of an object at infinity is formed on the retina.The focal length $f$ of the eye system is given by $f = \frac{1}{P}$.$f = \frac{1}{60}\, m = \frac{100}{60}\, cm = \frac{5}{3}\, cm$.$f \approx 1.67\, cm$.Since the image is formed on the retina,the distance between the retina and the cornea-eye lens is equal to the focal length of the eye system,which is $1.67\, cm$.

For a normal eye,the cornea of the eye provides a converging power of $40\, D$ and the least converging power of the eye lens behind the cornea is $20\, D$. Using this information,the distance between the retina and the cornea-eye lens can be estimated to be ......... $cm$.

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